Question

- pomogite pojaluysta)

Answer 1

2(1-sin^2x)+2sinx-2,5=0
2-2sinx^2+2sinx-2,5=0
2sin^2x-2sinx+0,5=0 ×2
4sin^2x-4sinx+1=0
sinx=a
4a^2-4a+1=0
D=16-16=0
x=4/8=1/2
sinx=1/2
x=+-п/6+2пк