Question

16^n-2 - 2^n-3/ 8^2n -4

Answer 1

$cfrac{16^{n-2}-2^{n-3}}{8^{2n-4}}=cfrac{2^{4n-8}-2^{n-3}}{2^{6n-12}}=cfrac{2^{4n-8}}{2^{6n-12}}-cfrac{2^{n-3}}{2^{6n-12}}=\\2^{4n-8-6n+12}-2^{n-3-6n+12}=2^{4-2n}-2^{9-5n}=4^{2-n}-2^{9-5n}$