Question

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Answer 1

$lim_{n to 4} frac{ x^{2} -16}{x-4} = [ frac{0}{0} ]= lim_{n to 4} frac{2x}{1} =8$

$lim_{n to 1} frac{ x^{3} -1}{x-1} =[ frac{0}{0} ]= lim_{n to 1} frac{3 x^{2} }{1} =3$