Question

√2 sin (п/4 - х/2)=>1 решить неравенство

Answer 1

sin(π/4 - x/2) ≥ 1/√2
sin(x/2 - π/4) ≤ - 1/√2

- 3π/4 + 2πn ≤ x/2 - π/4 ≤ - π/4 + 2πn
- π/2+ 2πn ≤ x/2  ≤  2πn
 - π+ 4πn ≤ x  ≤  4πn