Question

lim (x^3-8)/x^2+x-6
x (стрелка) 2

Answer 1

$\lim\limits _{x \to 2} \; \frac{x^3-8}{x^2+x-6} = \lim\limits _{x \to 2} \frac{(x-2)(x^2+2x+4)}{(x-2)(x+3)} = \lim\limits _{x \to 2} \frac{x^2+2x+4}{x+3} = \frac{4+4+4}{2+3} = \frac{12}{5}$