Question

решите систему уравнений
{(х+3)/4 - (у+2)/2 = 0
{3х + у = 1

Answer 1

{(х+3)/4 - (у+2)/2 = 0 |*4
{3х + у = 1
{x+3-2y-4=0
{3x+y=1
{x-2y=1
{3x+y=1|*2
+{x-2y=1
+{6x+2y=2
7x=3|:7
x=3/7
3/7-2y=1
-2y=1-3/7
-2y=4/7|:(-2)
y=-2/7