Question

Решите прошу срочно надо @!!!!!!!!!!!!@@!!!!@@!!!!!!

Answer 1

1. f'(x)=(ctg(x))'=-1/(sin^2(x))
    f'(x0)=-1/(sin^2(pi/3))=-4/3
2.  f'(x)=(1/x+lnx)'=(1/x^2+1/x)=-(1 - x)/x^2
      f'(x0)=-(1 - 0.5)/(0.5)^2=-0.5(1/4)=-2