Question

Помогите решить неравенство, пожалуйста

Answer 1

 (25+20x+4*(x^2))^(1/2)<3

Answer 2

$\sqrt{25+20x+4 x^{2}}\ \textless \ 3\\25+20x+4 x^{2} \ \textless \ 9\\4 x^{2} +20x+16\ \textless \ 0\\ x_{12}= \frac{-5+-3}{2}\\x_{1}=-4\ ;\ x_{2}=-1\\x\ \textless \ 0:(-4;-1)$