Question

Найти интеграл : |(2x^3-3x^2+1)dx

Answer 1

∫ (2x^3 - 3x^2 + 1) dx = 
= 2∫ x^3 dx - 3∫ x^2 dx + ∫ 1 dx = 
= 2*x^4/4 - 3*x^3/3 + x + C =
= x^4/2 - x^3 + x + C