Ответы
Ответ дал:
2
k=f'(x₀)
x₀=4
![y'(x)=( \frac{2}{x}-3 \sqrt{x} )'=2*( \frac{1}{x} )'-3*( \sqrt{x} )'=2*(- \frac{1}{ x^{2} } )-3* \frac{1}{2 \sqrt{x} } = y'(x)=( \frac{2}{x}-3 \sqrt{x} )'=2*( \frac{1}{x} )'-3*( \sqrt{x} )'=2*(- \frac{1}{ x^{2} } )-3* \frac{1}{2 \sqrt{x} } =](https://tex.z-dn.net/?f=y%27%28x%29%3D%28+%5Cfrac%7B2%7D%7Bx%7D-3+%5Csqrt%7Bx%7D++%29%27%3D2%2A%28+%5Cfrac%7B1%7D%7Bx%7D+%29%27-3%2A%28+%5Csqrt%7Bx%7D+%29%27%3D2%2A%28-+%5Cfrac%7B1%7D%7B+x%5E%7B2%7D+%7D+%29-3%2A+%5Cfrac%7B1%7D%7B2+%5Csqrt%7Bx%7D+%7D+%3D)
![=- \frac{2}{ x^{2} } - \frac{3}{2 \sqrt{x} } =- \frac{2}{ x^{2} } - \frac{3}{2 \sqrt{x} }](https://tex.z-dn.net/?f=%3D-+%5Cfrac%7B2%7D%7B+x%5E%7B2%7D+%7D+-+%5Cfrac%7B3%7D%7B2+%5Csqrt%7Bx%7D+%7D+)
![y'(4)=- \frac{2}{ 4^{2} }- \frac{3}{2 \sqrt{4} } =- \frac{1}{8} - \frac{3}{4} =- \frac{7}{8} =-0,875 y'(4)=- \frac{2}{ 4^{2} }- \frac{3}{2 \sqrt{4} } =- \frac{1}{8} - \frac{3}{4} =- \frac{7}{8} =-0,875](https://tex.z-dn.net/?f=y%27%284%29%3D-+%5Cfrac%7B2%7D%7B+4%5E%7B2%7D+%7D-+%5Cfrac%7B3%7D%7B2+%5Csqrt%7B4%7D+%7D++%3D-+%5Cfrac%7B1%7D%7B8%7D+-+%5Cfrac%7B3%7D%7B4%7D+%3D-+%5Cfrac%7B7%7D%7B8%7D+%3D-0%2C875)
k=-0,875 или k=-7/8
x₀=4
k=-0,875 или k=-7/8
Вас заинтересует
5 месяцев назад
5 месяцев назад
1 год назад
2 года назад