Question

Найдите нули функции
$y=-3x^{2}+2x + 1$

Answer 1

-3x²+2x+1=0
3x²-2x-1=0
D=4+12=16   √D=4
x1=1/8[2+4]=1/4+1/2=0.75
x2=1/8[2-4]=-0.25