Question

Решите пожалуйста очень надо

Answer 1

$\sqrt{3}cos^2(\frac{5\pi}{12})-\sqrt{3}sin^2(\frac{5\pi}{12})=\sqrt{3}[cos^2(\frac{5\pi}{12})-sin^2(\frac{5\pi}{12})]=\\\sqrt{3}cos(2*\frac{5\pi}{12})=\sqrt{3}cos(\frac{5\pi}{6})=\sqrt{3}*\frac{-\sqrt{3}}{2}=-1,5$