Question

Почему неправильно?

Answer 1

(log2(x^2))^2-16log2(2x)+31    x^2>0 x>0
4(log2(x))^2-16(log2(2)+log2(x))+31=0
4(log2(x))^2-16-16log2(x)+31=0
log2(x)=a  
4a^2-16a+15=0
D=64-60=4
a1=(8+2)/4=10/4=5/2
a2=(8-2)/4=6/4=3/2
log2(x)=5/2   x=2^(5/2)=4√2
log2(x)=3/2  x=2^(3/2)=2√2