Question

Помогите пожалуйста

Answer 1

(b³-8)/(b²-9)*(b+3)/(b²+2b+4)=
(b-2)(b²+2b+4)/(b-3)(b+3)*(b+3)/(b²+2b+4)=
(b-2)/(b-3)
(c²+6c+9)/(c³+27)*(c²-3c-9)/(3c+9)=
(c+3)²/(c+3)(c²-3c+9)*(c²-3c-9)/3(c+3)=
1/3

Answer 2

Ответ на фото!!!!!!!!!!!!!!!!