Question

Спростити вираз:!!!!!!!!!!!!!!!

Answer 1

якось так))))))))))))

Answer 2

$\frac{3a}{a-4}- \frac{a+2}{2a-8} \cdot \frac{96}{a^2+2a} = \frac{3a}{a-4}- \frac{a+2}{2(a-4)} \cdot \frac{96}{a(a+2)} =\frac{3a}{a-4}- \frac{48}{a(a-4)} =\\ =\frac{3a^2-48}{a(a-4)} =\frac{3(a^2-16)}{a(a-4)} =\frac{3(a-4)(a+4)}{a(a-4)} =\frac{3(a+4)}{a} =3+ \frac{12}{a}$