Question

sin п(3-х)/6=-корень3/2

Answer 1

1)pi(3-x)/6=-pi/3+2pi*n
(3-x)6=-1/3+2n
3-x=-2+12n
x=5-12n
2) pi(3-x)/6=-2pi/3+2pi*n
(3-x)6=-2/3+2n
3-x=-4+12n
x=7-12n
Ответ: x1=5-12n; x2=7-12n