Question

решите пж срочно надо

Answer 1

1)x²/y³+1/x=(x³+y³)/xy³
2)x/y²-1/y+1/x=(x²-xy+y²)/xy²
3)(x³+y³)/xy³:(x³-xy+y³)/xy²=(x+y)(x²-xy+y²)/xy³ * xy²/9x²-xy+y²)=(x+y)/y
4)[(x-y)²+4xy]:(1+y/x)=(x²-2xy+y²+4xy):(x+y)/x=(x+y)²*x/(x+y)=x(x+y)
5)(x+y)/y :x(x+y)=(x+y)/y*1/x(x+y)=1/(xy)