Question

$frac{ x^{2} + 4x}{2x+ 4} = 126$

Answer 1

ОДЗ:
2x + 4 ≠ 0 
2x ≠ -4
x ≠ -2


$x^2 + 4x = 126(2x + 4) \ \ x^2 + 4x = 252x + 504 \ \ x^2 - 248x - 504 = 0 \ \ x^2 - 248x + 15376 - 15880 = 0 \ \ (x - 124)^2 - (2 sqrt{3970})^2 = 0 \ \ (x - 124 - 2 sqrt{3970} )(x - 124 + 2 sqrt{3970} ) = 0 \ \ x = 124 + 2 sqrt{3970} and x = 124 - 2 sqrt{3970}$