Question

√(37-5√(48)) не могу решить

Answer 1

37-5√48=37-5√(16*3)=37-20√3=25-2*5*2√3+12=5²-2*5*2√3+(2√3)²=
=(5-2√3)²
√(5-2√3)²=|5-2√3|=5-2√3

Answer 2

$\mathtt{\sqrt{37-5\sqrt{48}}=\sqrt{37-5\sqrt{16*3}}=\sqrt{37-20\sqrt3}=}\\\mathtt{\sqrt{5^2-20\sqrt3+(2\sqrt{3})^2}=\sqrt{(5-2\sqrt3)^2}=|5-2\sqrt3|=5-2\sqrt3}\\\mathcal{OTVET:}\mathtt{5-2\sqrt3}}$