Question

$16 x^{2} -24x+5=0$

Answer 1

16x²-25x+5=0
D=(-24)²-4*16*5=576-320=√256
$x1=\frac{24+16}{32}= \frac{40}{32} = \frac{5}{4} =1.25 \\ x2= \frac{24-16}{32} = \frac{8}{32} = \frac{1}{4} =0.25$
отв:x1=1.25 , x2=0.25

Answer 2

$16x^2-24x+5=0$
$D = 24^2-(4*16*5) = 576-320=256=16^2$
$x_{1}= \frac{24+16}{32} = \frac{40}{32} =1,25$
$x_{2}=\frac{24-16}{32} = 0,25$
x1= 1,25; x2=0,25