Question

Помогите очень срочно
(2а/(2а-1)+1):(4а2-а)/(6а-3)

Answer 1

2a/(2a-1) +1=(2a+2a-1)/(2a-1)=(4a-1)/(2a-1)
(4a-1)/(2a-1):(4a²-a)/(6a-3)=(4a-1)/(2a-1) *3(2a-1)/a(4a-1)=3/a