Question

Упростить выражение
д) (9n+27)/(3n^2-n^3 )+((3n+9)/(n-3))^2∙(1/(3n-9)+2/(9-n^2 )-1/(n^2+3n))

Answer 1

(9n+27)/(3n^2-n^3 )+((3n+9)/(n-3))^2∙(1/(3n-9)+2/(9-n^2 )-1/(n^2+3n)) = $frac{3*(n+3)}{ n^{2} }$ (или $frac{9}{ n^{2} }$ + $frac{3}{n}$)