Question

решите уравнение 4 степени
6x^4-19x^3-x^2+11x+3=0

Answer 1

$6x^4-6x^3-13x^3+13x^2-14x^2+14x-3x+3=0\ 6x^3(x-1)-13x^2(x-1)-14x(x-1)-3(x-1)=0\(x-1)(6x^3-13x^2-14x-3)=0\ x-1=0\ x_1=1\ 6x^3-13x^2-14x-3=0\ 6x^3-18x^2+5x^2-15x+x-3=0\ 6x^2(x-3)+5x(x-3)+x-3=0\ (x-3)(6x^2+5x+1)=0\ x-3=0\ x_2=3\ 6x^2+5x+1=0\ D=25-24=1\ x_3=-0.5\ x_4=- frac{1}{3}$