Question

Даю 30 б
Разложите на множители

Answer 1

(x+y)²-64)=(x+y-8)(x+y+8)
(m+4n)²-b²=(m+4n-b)(m+4n+b)
y³(x²-1)-y(x-1)=y³(x-1)(x+1)-y(x-1)=y(x-1)(y²x+y²-1)
(a+3)(a²-3a+9)-a)3+a)=(a+3)(a²-3a+9-a)=(a+3)(a²-4a+9)
(b+4a)(b²-4a+16a²)+(b+4a)²=(b+4a)(b²-4a+16a²+b+4a)=(b+4a)(b²+b+16a²)
(x-3y)²-(a+1)²=(x-3y-a-1)(x-3y+a+1)
(2x-1)²-y²=(2x-1-y)(2x-1+y)
x²-y²+6x-4y+5=(x+3)²-(y+2)²=(x+3-y-2)(x+3+y+2)