Question

решите уравнение:(х+3)(х-2)-(х-3)(х+2)-5=6х-7
решите неравенство (х+2)(х-6)-(х-7)(х+7)<30-3х

Answer 1

(х+3)(х-2)-(х-3)(х+2)-5=6х-7

$x^{2} +3x-2x-6 - x^{2} +3x-2x+6 = 6x-7\ 2x=6x-7\ 2x-6x=-7\ -4x=-7\ x=1,75\ (x+2)(x-6)-(x-7)(x+7) leq 30-3x\ x^{2} +2x-6x-12- x^{2} +49 leq 30-3x\ -4x+3x leq 30+12-49\ -x leq -7\ x geq 7\ (7; +oo)$