Question

2cos^2+cosx sinx=0
Помогите

Answer 1

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Answer 2

2cos²x + cosxsinx = 0
cosx(2cosx + sinx) = 0
cosx = 0
x = π/2 + πn, n ∈ Z
sinx = -2cosx
tgx = -2
x = arctg(-2) + πn, n ∈ Z
Ответ: x = arctg(-2) + πn, n ∈ Z; π/2 + πn, n ∈ Z.