Question

Решите уравнение плиз

Answer 1

.......... ...........

Answer 2

OДЗ: х≠3,-3.
$frac{2x-2}{x+3}- frac{18}{x^2-9}= frac{x-6}{x-3}\ frac{2x-2}{x+3}- frac{18}{(x-3)(x+3)}= frac{x-6}{x-3}\ (x-3)(x+3)* frac{2x-2}{x+3}-(x-3)(x+3)* frac{18}{(x-3)(x+3)}=\=(x-3)(x+3)* frac{x-6}{x-3}\ (2x-2)(x-3)-18=(x+3)(x-6)\ 2x^2-6x-2x+6-18=x^2-6x+3x-18\ 2x^2-8x+6=x^2-3x\ 2x^2-8x+6-x^2+3x=0\ x^2-5x+6=0\ x_1*x_2=6\ x_1+x_2=5\ x_1=2\ x_2=3(ne//udovletvorayet).\ OTBET: x=2.$