Question

(1+а^-2/1-а^-2)^-1
Задание по алгебре

Answer 1

1+1/a²=(a²+1)/a²
1-1/a²=(a²-1)/a²
(a²+1)/a²:(a²-1)/a²=(a²+1)/a² *a²/(a²-1)=(a²+1)/(a²-1)
[(a²+1)/(a²-1)]^-1=(a²-1)/(a²+1)