Question

уравнение 3/(х+2)-3/(2-х)=2/(х^2-4)

Answer 1

3/(х+2)+3/(х-2)-2/(х^2-4)
3*(x-2)+3*(x+2)-2=0, x^2-4≠0,
3*x-6+3*x+6-2=0, x≠2, x≠-2,
6*x-2=0
x=1/3