Question

1) 5(x+2)+14<6-x
2) 2(3z+1)-x>3(x+4)
3) 4(3y-1)-3(y-1)>2(3+y)

Answer 1

1) 5х+10+14<6-х
5х+х<6-10-14
6х<-18
х<-3
2)6x+2-x>3x+12
6x-x-3x>12-2
2x>10
x>5
3)12y-4-3y+3>6+2y
12y-3y-2y>6-3+4
7y>7
y>1