Question

если f(x)=x^2+3x-40 то решите уравнение f(x)+f'(x)=0

Answer 1

f'(x) = 2x + 3

x² + 3x - 40 + 2x + 3 = 0
x² + 5x - 37 = 0
D = 25 + 148 = 173

x1 = (-5 - √173)/2
x2 = (-5 + √173)/2