Question

система 2x-y=0
3x^2 - y^2 +4=0

Answer 1

$begin{cases}2x-y=0,\3x^2-y^2+4=0;end{cases}, begin{cases}y=2x,\3x^2-4x^2+4=0;end{cases}\ begin{cases}y=2x,\(2-x)(2+x)=0;end{cases}, begin{cases}y=2x,\x_{1,2}=pm 2;end{cases}\ left{begin{matrix}x_1=-2\ y_1=-4end{matrix},left{begin{matrix}x_2=2\ y_2=4end{matrix}$