Question

Помогите!!!!
у=1/ log2 (х+3)
область определения

Answer 1

y=1/log2(x+3)

$log_2(x+3) textgreater 0 \ log_2(x+3) textgreater log_22^0 \ x+3 textgreater 1 \ x textgreater -2$

x∈(-2;+∞)