Question

Решите систему неравенств 5х+3>0 1/2х-4<0

Answer 1

$begin{cases}5x+3 textgreater 0,\ frac{1}{2}x-4 textless 0.end{cases},begin{cases}5x textgreater -3,\ frac{1}{2}x textless 4.end{cases},begin{cases}x textgreater -frac{3}{5}=-0.6,\ x textless 8.end{cases}\ xin(0.6;8)$