Question

z1+z2=3i+(2-3i)
z1+z2=(6+2i)-(7+2i)
Z1•z2=(3-2i)•(4+3i)

Answer 1

z₁+z₂=2+(3-3)i=2+0i=2
z₁+z₂=(6-7)+(2-2)i=-1+0i=-1
z₁z₂=12+9i-8i-6i²=12+i+6=18+i
i²=-1

Answer 2

4 с минусом поставили