Question

1)2 (х-3)=-3 (х+7)
2)6:х-5=х:3-х
3)4 (у+7)-7 (9-у)=у-5

Answer 1

2(x-3)=-3(x+7)
2x-6=-3x-21
2x+3x=21+6
5x=15
x=3
2)6/x-5=x/3-x
6/x-5=-2/3x
6/x-5+2/3x=0
$frac{18-15x+2x^2}{3x} =0 \ 2x^2-15x+18=0 \ x= frac{-(-15)+- sqrt{(-15)^2-4*2*18} }{2*2}= frac{15+-9}{4} \ x _{1}=6 x_{2} =1,5$
3)4(y+7)-7(9-y)=y-5
4y+28-63+7y=y-5
11y-35=y-5
11y-y=-5+35
10y=30
y=3

Answer 2

2х-6=-3х-21
2х+3х= -21+6
5х=-15
х=-3