Question

Очень срочно нужно 9 класс

Answer 1

1a) 2Cos60° + √3*Cos30° = 2*1/2 + √3* √3/2 = 2 + 3/2 = 2,5
б) √3*Sin60° - √2*Cos45° = √3* √3/2 - √2*1/√2 = 3/2 - 1 = 0,5
2a) Sin0° - Cos180° = 0 - (- 1) = 1
б) 7Sin180° + 3Cos90° = 7*0 + 3* 0 = 0

Answer 2

1a) √2*Sin45° - √3* Cos30° = √2* 1/√2 - √3* √3/2 = 1 - 3/2 = - 0,5 б)4Cos60° - Sin30° = 4*1/2 - 1/2 = 1,5 в) 4Sin90° - 5tg180° = 4*1 - 5*0= 4 г)Cos0° + Cos180° = 1 - 1 = 0

Answer 3

https://znanija.com/task/25419624 пожалуйста

Answer 4

https://znanija.com/task/25419608