Question

Срочно 20баллов алгебра

Answer 1

$frac{3a^2+6}{a^3+1} - frac{3}{a^2-a+1} - frac{1}{a+1} = frac{3a^2+6}{(a+1)(a^2-a+1)} - frac{3}{a^2-a+1} - frac{1}{a+1}= \= frac{3a^2+6-3(a+1)-(a^2-a+1)}{(a+1)(a^2-a+1)} = frac{3a^2+6-3a-3-a^2+a-1}{(a+1)(a^2-a+1)} = frac{2a^2-2a+2}{(a+1)(a^2-a+1)} = \= 2frac{a^2-a+1}{(a+1)(a^2-a+1)} = frac{2}{a+1} = frac{2}{-1,4+1} = -frac{2}{0,4} =-5$