Question

Как найти производную функции?

Answer 1

 $f'((x+1)*3^x^-^1)=$
$f'(x+1)*3^x^-^1+(x+1)*f'(3^x^-^1)=$
$f'(x)*3^x^-^1+ln(3)*(x+1)*f'(x-1)*3^x^-^1=$
$3^x^-^1+ln(3)*f'(x)*(x+1)*3^x^-^1=$
$3^x^-^1+ln(3)*(x+1)*3^x^-^1=$
$3^x^-^1+ln(3)*x*3^x^-^1+ln(3)*3^x^-^1=$
$3^x^-^1*(ln(3)*x+ln(3)+1)$