Question

Помогите пожалуйста. У меня есть только 10 минут. Просто ответы

Answer 1

$********\mathtt{2^{dfrac{1}{3}+dfrac{1}{4}-dfrac{1}{12}}}\\\mathtt{2^{dfrac{7}{12}-dfrac{1}{12}}}\\\mathtt{2^{dfrac{6}{12}}}\\\mathtt{2^{dfrac{1}{2}}}\\\mathtt{[sqrt{2}]^2}\boxed{textbf{2}}\\********\mathtt{x=y^2} \mathtt{y^{-1}=dfrac{y^{-2}}{3}} \mathtt{3=dfrac{1}{y}} \mathtt{y=dfrac{1}{3}} \mathtt{x=y^2=dfrac{1}{9}} \\\********\mathtt{x^{0,5}=y}\mathtt{x=y^2}\mathtt{=(dfrac{y^3-1}{y-1}+y):(dfrac{y^2-1}{y-1}}}\\mathtt{=(y^2+y+1+y):(y+1)}\mathtt{=dfrac{(y+1)^2}{(y+1)}} \mathtt{=y+1}\mathtt{=x^{0,5}+1}\textbf{Bac{s}ari lar}\textsf{iyi dersler}$

Answer 2

döktürmüşüz:)

Answer 3

evet :)