Question

6^x-16×3^x-9×2^x+144

Answer 1

6^x-16×3^x-9×2^x+144 <= 0
2^x*3^x - 16 * 3^x  -  9* 2^x + 9*16 <=0
3^x*(2^x - 16) - 9*(2^x - 16) <= 0
(3^x - 9)(2^x - 16) <=0
(3^x - 3^2)(2^x - 2^4) <=0 
+++++++ 2 ------------- 4 +++++++++++
x∈[2 4]
ответ 2+3+4 = 9