Question

4.57. Упростите выражение (а≥0, b≥0):

Answer 1

√(30a⁷*45b³ *75b⁵*98a³) =√(3*2*5a⁷ *3*3*5b³  *5*5*3b⁵* 7*7*2a³) =

√(2²*3⁴*5⁴*7²a¹⁰*45b⁸ )=2*3²*5²*7a⁵b⁴=2*9*25*7a⁵b⁴  =3150 a⁵b⁴



√(12a¹⁷*21b³*24b⁵*42a³ )=√(2*2*3a¹⁷* 3*7b³* 2*2*2*3b⁵* 2*3*7a³ ) =

=√(2⁶*3⁴*7²*a²⁰b⁸ )=2³*3²*7a¹⁰b⁴=8*9*7a¹⁰b⁴= 504a¹⁰b⁴