Question

докажите, что верно равенство

Answer 1

1 / (a-b)(a-c) - 1/(a-b)(b-c) + 1/(a-c)(b-c) =  b-c-a+c+a-b /(a-b)(a-c)(b-c) = 0 /(a-b)(a-c)(b-c) = 0

Answer 2

1/(a-b)(a-c) + 1/(b-a)(b-c) - 1/(c-a)(b-c) =0
1)1/(a-b)(a-c) -1/(a-b)(b-c) =b-c-a+c/(a-b)(a-c)(b-c) =b-a/(a-b)(a-c)(b-c) = -1/(a-c)(b-c)
2)-1/(a-c)(b-c) + 1/(a-c)(b-c) =0