Ответы
Ответ дал:
0
Решение по действиям:
![1) frac{3n}{n-4}- frac{6n}{n^2-8n+16}= frac{3n}{n-4}- frac{6n}{(n-4)^2}=frac{3n(n-4)-6n}{(n-4)^2}=frac{3n^2-12n-6n}{(n-4)^2}=\\=frac{3n^2-18n}{(n-4)^2}=frac{3n(n-6)}{(n-4)^2} \\\
2) frac{3n(n-6)}{(n-4)^2} : frac{n-6}{16-n^2} =frac{3n(n-6)}{(n-4)^2} * frac{-(n+4)(n-4)}{n-6} = frac{-3n(n+4)}{n-4} =frac{-3n^2-12n}{n-4} \\\
3) frac{-3n^2-12n}{n-4} + frac{24n}{n-4}= frac{-3n^2+12n}{n-4}= frac{-3n(n-4)}{n-4}=-3n](https://tex.z-dn.net/?f=1%29+++frac%7B3n%7D%7Bn-4%7D-+frac%7B6n%7D%7Bn%5E2-8n%2B16%7D%3D+frac%7B3n%7D%7Bn-4%7D-+frac%7B6n%7D%7B%28n-4%29%5E2%7D%3Dfrac%7B3n%28n-4%29-6n%7D%7B%28n-4%29%5E2%7D%3Dfrac%7B3n%5E2-12n-6n%7D%7B%28n-4%29%5E2%7D%3D%5C%5C%3Dfrac%7B3n%5E2-18n%7D%7B%28n-4%29%5E2%7D%3Dfrac%7B3n%28n-6%29%7D%7B%28n-4%29%5E2%7D+%5C%5C%5C%0A2%29++frac%7B3n%28n-6%29%7D%7B%28n-4%29%5E2%7D+%3A+frac%7Bn-6%7D%7B16-n%5E2%7D+%3Dfrac%7B3n%28n-6%29%7D%7B%28n-4%29%5E2%7D+%2A+frac%7B-%28n%2B4%29%28n-4%29%7D%7Bn-6%7D+%3D+frac%7B-3n%28n%2B4%29%7D%7Bn-4%7D+%3Dfrac%7B-3n%5E2-12n%7D%7Bn-4%7D+%5C%5C%5C%0A3%29++frac%7B-3n%5E2-12n%7D%7Bn-4%7D+%2B+frac%7B24n%7D%7Bn-4%7D%3D+frac%7B-3n%5E2%2B12n%7D%7Bn-4%7D%3D++frac%7B-3n%28n-4%29%7D%7Bn-4%7D%3D-3n "1) frac{3n}{n-4}- frac{6n}{n^2-8n+16}= frac{3n}{n-4}- frac{6n}{(n-4)^2}=frac{3n(n-4)-6n}{(n-4)^2}=frac{3n^2-12n-6n}{(n-4)^2}=\\=frac{3n^2-18n}{(n-4)^2}=frac{3n(n-6)}{(n-4)^2} \\\
2) frac{3n(n-6)}{(n-4)^2} : frac{n-6}{16-n^2} =frac{3n(n-6)}{(n-4)^2} * frac{-(n+4)(n-4)}{n-6} = frac{-3n(n+4)}{n-4} =frac{-3n^2-12n}{n-4} \\\
3) frac{-3n^2-12n}{n-4} + frac{24n}{n-4}= frac{-3n^2+12n}{n-4}= frac{-3n(n-4)}{n-4}=-3n")
Ответ дал:
0
Большое спасибо!
Вас заинтересует
1 год назад
2 года назад
8 лет назад
8 лет назад