Question

Разложить на множители квадратный трехчлен
1)x^2-8x+16
2)3y^2-5y+2

Answer 1

$1)  x^{2}-8x+16 = x^{2}-4x-4x+16 = x(x-4) - 4(x-4) = (x-4)(x-4) 2)  3y^{2} -5y+2= 3y^{2}-3y-2y+2 = 3y(y-1) -2(y-1) = (3y-2)(y-1)$

Answer 2

1) x^2 - 8x + 16 = x^2 -4x -4x + 16 = x(x-4) -4(x-4) = (x-4)(x-4)

Answer 3

а 2

Answer 4

2)3y^2 - 5y + 2 = 3y^2 - 3y - 2y + 2 = 3y(y-1) - 2(y-1) = (3y-2)(y-1)

Answer 5

спс