Question

Решите пожалуйста 9 хадание

Answer 1

$left { {{x^2-8x geq 0} atop {4x+28 neq 0}} right. \ left { {{x(x-8) geq 0} atop {4x neq -28}} right. \ left { {{x leq 0, x geq 8} atop {x neq -7}} right. \ x in (-infty ; -7) cup (-7;0] cup [8; +infty )$