Question

Решите систему
{x^2+2y^2=33
{2x^2-y^2=46

Answer 1

$x^2+2y^2=33 \ 2x^2-y^2=46 \ \ 2x^2+4y^2=66 \ - \ 2x^2-y^2=46 \ \ 5y^2=20 \ y^2=4 \ y=б2 \ \ x= бsqrt{33-2*4}=бsqrt{25}=б5$

Ответ: (5;2), (5;-2), (-5;2), (-5;-2)