Question

Разложите на множители:5y^2+9y-2

Answer 1

5y^2+9y-2=0; D=9^2-4*5*(-2)=81+40=121; y1=(-9-11)/10, y2=(-9+11)/10. y1= -2, y2=1/5.  5y^+9y-2=5*(y-1/5)*(y+2)=(5y-1)*(y+2).