Question

1-cos2x+sinx=0 помогите

Answer 1

1-cos2x+sinx=0    cos2x=1-2sin²x
1-1+2sin²x+sinx=0
sinx(2sinx+1)=0
sinx=0  x=πk   k∈Z
sinx=-1/2  x=(-1)ⁿ⁺¹π/6+πn  n∈Z