Question

(2a/b^2-1/2a):(1/b+1/2a)

Answer 1

$displaystyle ( frac{2a}{b^{2}}- frac{1}{2a}):( frac{1}{b}+ frac{1}{2a})= frac{4a^{2}-b^{2}}{2ab^{2}}* frac{2ab}{2a+b}= frac{(2a-b)(2a+b)}{b(2a+b)}= \ \ = frac{2a-b}{b}= frac{2a}{b}-1;$